(x^2-5)/(16-x^2)=7

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Solution for (x^2-5)/(16-x^2)=7 equation: 


D( x )

16-x^2 = 0

16-x^2 = 0

16-x^2 = 0

-1*x^2 = -16 // : -1

x^2 = 16

x^2 = 16 // ^ 1/2

abs(x) = 4

x = 4 or x = -4

x in (-oo:-4) U (-4:4) U (4:+oo)

(x^2-5)/(16-x^2) = 7 // - 7

(x^2-5)/(16-x^2)-7 = 0

(x^2-5)/(16-x^2)+(-7*(16-x^2))/(16-x^2) = 0

x^2-7*(16-x^2)-5 = 0

8*x^2-117 = 0

(8*x^2-117)/(16-x^2) = 0

(8*x^2-117)/(16-x^2) = 0 // * 16-x^2

8*x^2-117 = 0

8*x^2 = 117 // : 8

x^2 = 117/8

x^2 = 117/8 // ^ 1/2

abs(x) = (117/8)^(1/2)

x = (117/8)^(1/2) or x = -(117/8)^(1/2)

x in { (117/8)^(1/2), -(117/8)^(1/2) }

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